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60k=12k^2
We move all terms to the left:
60k-(12k^2)=0
determiningTheFunctionDomain -12k^2+60k=0
a = -12; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·(-12)·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*-12}=\frac{-120}{-24} =+5 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*-12}=\frac{0}{-24} =0 $
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